To see how the acceleration that a cart relies on the resultant force acting on the cart and also the mass of the cart, and also how this relation have the right to be express in a solitary equation. We hypothesized that with a consistent mass that the system (a diminish in cart mass) and an raised net force, acceleration would certainly increase. Also, with an raised mass the the cart and also a consistent net force, acceleration would stay the same.

You are watching: Slope of acceleration vs force graph

Apparatus and also Materials

Dynamics cartThree 200.0 g massesTwo 1.0 kg massesStringPulley/Photogate2 clampsLabProTM InterfaceLoggerProTM AnalysisDigital Balance


“Investigation 2.3.1” Physics 11. Toronto: Nelson Thomson Learning, 2002. 68-70.

Observations and Calculations

Run NumberMass of system (Msys)1/ mass of SystemNet pressure (of Hanger)Net Force/Mass that SystemAcceleration
A-11.54 kgn/a1.96 N1.27 N/kg1.08 m/s2
A-21.54 kgn/a3.92 N2.55 N/kg2.24 m/s2
A-31.54 kgn/a5.88 N3.82 N/kg3.42 m/s2
B-11.54 kg0.649 1/kg5.88 N3.82 N/kg3.42 m/s2
B-22.54 kg0.394 1/kg5.88 N2.31 N/kg2.12 m/s2
B-33.54 kg0.282 1/kg5.88 N1.66 N/kg1.45 m/s2


Analysis (pg. 69-70):

c) view “Observations and Calculations”

d) see graph “Acceleration vs. Fnet”. The graph that acceleration as a duty of the net force indicates the there is a straight relationship between the net force and the acceleration together that once the net force is doubled the acceleration is also doubled.

e) The acceleration as a duty of the mass of the system shows that acceleration decreases as the mass of the mechanism increases. The graph says that a allude will be reached where over there is the opportunity of placing so much mass on the cart the the cart will strategy the suggest of zero acceleration.

f) watch graph “Acceleration vs. Reciprocal of Msys”. The steep of the acceleration vs. Reciprocal of the mass of the device (1/Mass of System)is in the unit m/s2/1/kg. One can change this come say kg m/s2 i m sorry is likewise known together N. Therefore, the steep of the graph to represent the net pressure acting on the cart.

g) check out “Observations and Calculations”. When comparing the calculate acceleration with the proportion Fnet/m one discovers that they are essentially the same. An equation to describe this relationship is: a = Fnet/m

h) check out graph “Acceleration vs. Fnet/m”. The acceleration points are basically the very same as the Fnet/m points, so: a = Fnet/m


k) In this lab, us were just looking in ~ the loved one difference between force and also acceleration and mass and acceleration. In this case, the frictional pressures were practically consistent throughout the lab, so they had actually no function in identify the outcome of the lab.

l) Some instances of systematic errors in this lab are that we don’t know if the balance or LoggerProTM were completely accurate due to possible calibration errors if the wheels and the wheel are no always transforming consistently, so more or less pressure would be required to pull it.

A case of arbitrarily error is that approximates were make to obtain the last far-reaching digit as soon as weighing the cart on the balance since the balance just goes to a specific amount of digits and rounds off the critical one.

Some instances of person error can be that possibly the cart was released before the LoggerProTM started recording the run, the “stop” switch on the LoggerProTM can have to be pressed as well early before the computer had finished recording the run, probably the cart was not perfectly aligned each time, so much more or less force would be essential to pull it.

m) correctly the equation a = Fnet/m applies to Newton’s an initial Law because if there is zero net pressure there is a consistent velocity or zero acceleration.

To enhance our results, we can have made absolutely certain that the human releasing the cart let pursue the other human pressed the “collect” switch on the LoggerProTM. We also could have actually made sure that over there was enough time because that the LoggerProTM come record every one of the results before we pressed the “stop” button. Us probably could have excellent each that the runs a couple of times in order because that the data come be completely accurate.


i) The acceleration that the cart will increase/decrease once the net force increases/decreases (the massive of the cart continues to be constant) or once the mass of the dare decreases/increases (the net force remains constant). From the graphs we check out that: a µ Fnet , and, a µ 1/m. Therefore, a = Fnet/m.

See more: How To Make Your Dick Bigger In Pictures ? How Do I Photograph My Dick So It Looks Bigger

j) The first part the our hypothesis stated, “…with a constant mass of the mechanism (a to decrease in cart mass) and also an raised net force, acceleration would increase.” This prediction was presented to be true top top the graph “Acceleration vs. Fnet” i beg your pardon is from component A of ours experiment.

This graph reflects the straight relationship between net force and also acceleration such that as soon as the net pressure increases acceleration rises as well. The second component of our hypothesis stated, “…with an boosted mass of the cart and also a consistent net force, acceleration would continue to be the same.”

This prediction was displayed to be incorrect ~ above the graphs “Acceleration vs. Fixed of System” and “Acceleration vs. Mutual of Msys” which are both from component B of our experiment. This graphs display the station relationship in between acceleration and the mass of the device such that as soon as the massive of the system rises the acceleration decreases. Therefore, our hypothesis of the experiment was partially correct.