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param visionsOctober 01, 20201 comment
Hollow mild stole square section

Here, thickness T = 2mm. Breadth B = 50mm and also length l =1m.

 Hollow stole square tube.

First, we will certainly calculate the sectional area in two parts, the orange-colored part area as A1, and green colored component area as A2.

Area A2 =< B - ( 2 × T ) × T × 2 nos>

= < 50mm. - ( 2 × 2mm. ) × 2mm. × 2 nos>

=< 46 mm× 2mm.×2nos.>

= 0.046× 0.002× 2

= 0.000184 square meter.

Now, total sectional area A = A1 +A2

= 0.0002 +0.000184

= 0.000384 square meter.

As friend know, volume = area× length

= A × L

= 0.000384× 1

= 0.000384 cubic meter.

The thickness of mild stole is 7850 kg./cum.

See more: In A Parallelogram A Diagonal Separates The Parallelogram Into ?

So, the weight of the hollow square multiple sclerosis tube

= volume× density

= 0.000384× 7850

= 3.014 kg.

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